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An infinite plane sheet of charge in vacuum has a uniform surface charge density $\sigma$. The electric field intensity near it is A $\frac{\sigma}{\varepsilon_{0}}$ B $\frac{\sigma}{2 \varepsilon_{0}}$ C $\frac{\sigma}{\varepsilon}$ D $\frac{\sigma}{2 \varepsilon}$
An infinite plane sheet of charge in vacuum has a uniform surface charge density $\sigma$. The electric field intensity near it is
A $\frac{\sigma}{\varepsilon_{0}}$
B $\frac{\sigma}{2 \varepsilon_{0}}$
C $\frac{\sigma}{\varepsilon}$
D $\frac{\sigma}{2 \varepsilon}$
Physics | Previous Year Question Papers
An infinite plane sheet of charge in vacuum has a uniform surface charge density $\sigma$. The electric field intensity near it is
A $\frac{\sigma}{\varepsilon_{0}}$
B $\frac{\sigma}{2 \varepsilon_{0}}$
C $\frac{\sigma}{\varepsilon}$
D $\frac{\sigma}{2 \varepsilon}$

Correct option is A $\frac{\sigma}{\varepsilon_{0}}$
Charge density $=\sigma$
Electric field intensity near it is –
Using gauss law,
$\lambda=\frac{\sigma}{\varepsilon_{0}}$

i

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