Correct option is c $E \neq 0$ if $\phi$ is changing.
Farady’s law states that time varying magnetic flux can induce an e.m.f. $\mathrm{E}=$ Electric field, Induced
$$
\mathrm{E}=-\frac{\mathrm{d} \phi}{\mathrm{dt}}
$$
$$
\begin{array}{l}
\mathrm{E}=-\frac{\mathrm{d} \phi}{\mathrm{dt}} \\
\mathrm{E}=0 \text { only if } \frac{\mathrm{d} \phi}{\mathrm{dt}}=0
\end{array}
$$
If $\mathrm{E}=0$, then $\phi=$ const.
$\mathrm{E} \neq 0$, then $\phi$ is changing
If the instantaneous magnetic flux and induced emf produced in a coil is $\phi$ and $E$ respectively, then according to Faraday’s law of electro magnetic induction:
A E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
c $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero
A E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
c $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero
If the instantaneous magnetic flux and induced emf produced in a coil is $\phi$ and $E$ respectively, then according to Faraday’s law of electro magnetic induction:
A E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
c $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero
A E must be zero if $\phi=0$ and changing
B $\quad E \neq 0$ if $\phi=0$
c $E \neq 0$ if $\phi$ is changing.
D $E=0$ then $\phi$ must be zero