Correct option is A $90 \mathrm{~J}$
efficiency of carnot cycle is given as
$$
\eta=\frac{W}{Q_{H}}
$$
where $W$ is work done and $Q_{H}$ is amount of heat added to system.
$$
\begin{array}{l}
\mathrm{Q}_{\mathrm{H}}=\frac{\mathrm{W}}{\eta}=100 \mathrm{~J} \\
\mathrm{Q}_{\mathrm{C}}=\mathrm{Q}_{\mathrm{H}}-\mathrm{W}=100-10=90 \mathrm{~J}
\end{array}
$$
A Carnot engine, having an efficiency of $\eta=\frac{1}{10}$ as heat engine, is used as a. refrigerator. If the work done on the system is $10 \mathrm{~J}$, the amount of energy absorbed from the reservoir at lower temperature is:
A $90 \mathrm{~J}$
B $1 \mathrm{~J}$
c $100 \mathrm{~J}$
D $99 \mathrm{~J}$
A $90 \mathrm{~J}$
B $1 \mathrm{~J}$
c $100 \mathrm{~J}$
D $99 \mathrm{~J}$
A Carnot engine, having an efficiency of $\eta=\frac{1}{10}$ as heat engine, is used as a. refrigerator. If the work done on the system is $10 \mathrm{~J}$, the amount of energy absorbed from the reservoir at lower temperature is:
A $90 \mathrm{~J}$
B $1 \mathrm{~J}$
c $100 \mathrm{~J}$
D $99 \mathrm{~J}$
A $90 \mathrm{~J}$
B $1 \mathrm{~J}$
c $100 \mathrm{~J}$
D $99 \mathrm{~J}$