$ (1)\,\,{{I}_{d}}={{V}_{0}}\omega C\cos \omega t $
$ (2)\,\,{{I}_{d}}=\frac{{{V}_{0}}}{\omega C}\cos \omega t $
$ (3)\,\,{{I}_{d}}=\frac{{{V}_{0}}}{\omega C}\sin \omega t $
$ (4)\,\,\,{{I}_{d}}={{V}_{0}}\omega C\sin \omega t $
Solution: Answer 1