(1) 602 s
(2) 230.3 s
(3) 301 s
(4) 2000 s
Correct Answer: (1) 602 s
Explanation:
For a first order reaction
40 g substance requires 2 half life periods to reduce upto 10 g
Time taken in reduction = 2 × 300.91s
= 601.82
= 602 s
A first order reaction has a rate constant of 2.303 × 10-3 s-1. The time required for 40 g of this reactant to reduce to 10 g will be [Given that log102 = 0.3010]
A first order reaction has a rate constant of 2.303 × 10-3 s-1. The time required for 40 g of this reactant to reduce to 10 g will be [Given that log102 = 0.3010]