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A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is
Physics | Physics
A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the Binding Energy in the process is

(1) 0.9 MeV

(2) 9.4 MeV

(3) 804 MeV

(4) 216 MeV

Solution: Answer (4)

Reactant mass number = 240
Reactant mass number = 240
The total number of products is 120.

BE per product nucleon = 8.5 MeV

Total BE gain = (BE) of products – (BE) of reactants.

= [120 + 120] × 8.5 – [240] × 7.6

= (240) × 8.5 – 240 × 7.6

= (2040 – 1824) MeV

216 MeV is the gain in BE

i

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