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A stone of mass 2kg attached at one end of the of a 2m long string is whirled in horizontal circle. The string makes an angle of 45 degrees with the vertical then the centripetal force acting on the string is
A stone of mass 2kg attached at one end of the of a 2m long string is whirled in horizontal circle. The string makes an angle of 45 degrees with the vertical then the centripetal force acting on the string is
MHTCET | Physics
A stone of mass 2kg attached at one end of the of a 2m long string is whirled in horizontal circle. The string makes an angle of 45 degrees with the vertical then the centripetal force acting on the string is
  1. 30 N
  2. 40 N
  3. 20 N
  4. 10 N

Solution: 20N

$ Given: $

$ m=2kg,\,r=2m,\,\,\theta ={{45}^{\circ }} $

$ Now,~\,Fsin\theta =\frac{m{{v}^{2}}}{r} $

$ and\,v=\sqrt{rg\tan \theta } $

$ v=\sqrt{2\times 9.8\times \tan {{45}^{\circ }}}=4.43\,m/s $

$ \because Centripetal\,force=\frac{m{{v}^{2}}}{r}=\frac{2\times 19.6}{2} $

$ Centripetal\,force=19.6\,N\approx 20\,N $

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