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Acetic acid on treatment with NaOH gives Y and with SOCl2 gives Z. Y and Z when heated form acetic anhydride. The compounds Y and Z respectively are:
Acetic acid on treatment with NaOH gives Y and with SOCl2 gives Z. Y and Z when heated form acetic anhydride. The compounds Y and Z respectively are:
Chemistry | MHTCET
Acetic acid on treatment with NaOH gives Y and with SOCl2 gives Z. Y and Z when heated form acetic anhydride. The compounds Y and Z respectively are:

 

 

 

Solution: Option 3 is correct

Sodium hydroxide (NaOH) reacts with acetic acid (CH3​COOH) to form sodium acetate (CH3​COONa) and water  (H2​O). The equation for this reaction can be written as :

NaOH + CH3​COOH → CH3​COONa + H2​O

So, Y = CH3​COONa (sodium acetate)

Now,

2CH3COOH + SOCl2 → 2CH3COCl + SO2 + H2O

So, Z = CH3COCl (acetyl chloride)

In the laboratory, acetic anhydride is made by distilling a combination of acetyl chloride and anhydrous sodium acetate.

 

 

So, Y = CH3​COONa (sodium acetate) and Z = CH3COCl (acetyl chloride)

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