All the three face cards of spades are removed from a well shuffled pack of 52 cards. A card is then drawn at random from the remaining pack. Find the probability of getting:(iii) a black card

(iii) Number of black cards left = 23 cards (13 club + 10 spade)

Event of drawing a black card = E = 23

So, n(E) = 23

Hence, probability of drawing a black card = n(E)/ n(S) = 23/49

i

In any reaction, catalyst
(A) retards the rate of reaction
(B) increases the rate of reaction
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(D) none of these

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$$ \text { If }\left(\tan ^{-1} x\right)^{2}+\left(\cot ^{-1} x\right)^{2}=\frac{5 \pi^{2}}{8}, \text { then } x \text { equals to } $$

If $A_{3 \times 3}$ and $\operatorname{det} A=6$, then $\operatorname{det}(2 \operatorname{adj} A):$

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