- 253.5 pm
- 353.5 pm
- 465 pm
- 250 pm
Solution: 353.5 pm
$ For\text{ }a~FCC~or~~CCP~unit\text{ }cell,we\,have: $
$ 4r=\surd 2\times a $
$ \Rightarrow a=\frac{4r}{\surd 2}=353.5pm $
Solution: 353.5 pm
$ For\text{ }a~FCC~or~~CCP~unit\text{ }cell,we\,have: $
$ 4r=\surd 2\times a $
$ \Rightarrow a=\frac{4r}{\surd 2}=353.5pm $