An ideal gas is permitted to grow against a consistent strain of 2 bar from 10 L to 50 L in one stage. Compute the measure of work done by the gas. In the event that a similar development were done reversibly, will the work is done be higher or lower than the prior case? \[\left( Considering\text{ }that\text{ }1\text{ }L\text{ }bar\text{ }=\text{ }100J \right)\]
An ideal gas is permitted to grow against a consistent strain of 2 bar from 10 L to 50 L in one stage. Compute the measure of work done by the gas. In the event that a similar development were done reversibly, will the work is done be higher or lower than the prior case? \[\left( Considering\text{ }that\text{ }1\text{ }L\text{ }bar\text{ }=\text{ }100J \right)\]

solution:

 

\[\begin{array}{*{35}{l}}

Measure\text{ }of\text{ }work\text{ }done\text{ }=\text{ }-\text{ }pext\text{ }V  \\

~  \\

=\text{ }\text{ }2\text{ }bar\text{ }\times \text{ }\left( 50\text{ }\text{ }10\text{ } \right)\text{ }L\text{ }=\text{ }\text{ }80\text{ }L\text{ }bar.  \\

~  \\

Presently,\text{ }it\text{ }is\text{ }given\text{ }that\text{ }1\text{ }L\text{ }bar\text{ }=\text{ }100\text{ }J  \\

~  \\

So\text{ },\text{ }-\text{ }80\text{ }L\text{ }bar\text{ }=\text{ }\left( -\text{ }80\text{ }\times \text{ }100 \right)\text{ }=\text{ }-\text{ }8000\text{ }J  \\

~  \\

\end{array}=\text{ }-\text{ }8\text{ }KJ\] is the measure of work done in the above interaction.

 

On the off chance that it is reversible, the interior strain will be bigger than the outside pressure. So the work done will claim a higher worth.