The number of electrons in a negatively charged ion be $x$.
Then, no. neutrons present $=x+11.1 \%$ of $x=x+0.111 x=1.111 x$
No. electrons present in the neutral atom $=(x-1)$
(When an ion carries a negative charge, it carries an extra electron)
No. protons present in the neutral atom $=\mathrm{x}-1$
Given, mass number of the ion $=37$
$
\begin{array}{l}
(x-1)+1.111 x=37 \\
2.111 x=38 \\
x=18
\end{array}
$
Hence, The symbol of the ion is ${ }_{17}^{37} \mathrm{Cl}^{-}$
An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.
An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.