Solution:
$\sin ^{-1}\left(\frac{-1}{2}\right)=-\sin ^{-1}\left(\frac{1}{2}\right)\left[\right.$ Formula: $\left.\sin ^{-1}(-x)=\sin ^{-1}(x)\right]$
$=-\frac{\pi}{6}$
Find the principal value of each of the following : $\sin ^{-1}\left(\frac{-1}{2}\right)$
Find the principal value of each of the following : $\sin ^{-1}\left(\frac{-1}{2}\right)$