Solution:
For $A$ to be singular matrix its determinant should be equal to 0 .
$\begin{array}{l}
0=(3-2 x) \times 4-(x+1) \times 2 \\
0=12-8 x-2 x-2 \\
0=10-10 x \\
x=1
\end{array}$
For what value of $x$, the given matrix $A=\left[\begin{array}{cc}3-2 x & x+1 \\ 2 & 4\end{array}\right]$ is a singular matrix?
For what value of $x$, the given matrix $A=\left[\begin{array}{cc}3-2 x & x+1 \\ 2 & 4\end{array}\right]$ is a singular matrix?