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If $\mathbf{A}^{\prime}=\left[\begin{array}{ll}-2 & 3 \\ 1 & 2\end{array}\right]$ and $\mathbf{B}=\left[\begin{array}{rr}-1 & 0 \\ 1 & 2\end{array}\right]$ then find $(A+2 B)$ ‘.
If $\mathbf{A}^{\prime}=\left[\begin{array}{ll}-2 & 3 \\ 1 & 2\end{array}\right]$ and $\mathbf{B}=\left[\begin{array}{rr}-1 & 0 \\ 1 & 2\end{array}\right]$ then find $(A+2 B)$ ‘.
CBSE | Class 12 | Exercise 3.3 | Maths | Matrices | NCERT
If $\mathbf{A}^{\prime}=\left[\begin{array}{ll}-2 & 3 \\ 1 & 2\end{array}\right]$ and $\mathbf{B}=\left[\begin{array}{rr}-1 & 0 \\ 1 & 2\end{array}\right]$ then find $(A+2 B)$ ‘.

$\left(A^{\prime}\right)^{\prime}=A=\left[\begin{array}{rr}-2 & 1 \\ 3 & 2\end{array}\right]$

$A+2 B$

$=\left[\begin{array}{ll}-2 & 1 \\ 3 & 2\end{array}\right]+2\left[\begin{array}{rr}-1 & 0 \\ 1 & 2\end{array}\right]=\left[\begin{array}{rr}-4 & 1 \\ 5 & 6\end{array}\right]$
And
$(A+2 B)^{\prime}=\left[\begin{array}{rr}-4 & 5 \\ 1 & 6\end{array}\right]$

i

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