In dictionary words are listed alphabetically, so to find the words

Listed before $E$ should start with letter either $A,\;B, \;C \;or \;D$

But the word $EXAMINATION$ doesn`t have $B,\;C \;or \;D$

Hence the words should start with letter $A$

The remaining $10\;places$ are to be filled by the remaining letters of the word $EXAMINATION$ which are $E,\; X,\; A,\; M,\; 2N, \;T,\; 2I, \;0$

Since the letters are repeating the formula used would be

Where $n$ is remaining number of letters \[{{p}_{1}}and\text{ }{{p}_{2}}\] are number of times the repeated terms occurs.

The number of words in the list before the word starting with $E$

\[=\text{ }words\text{ }starting\text{ }with\text{ }letter\text{ }A\text{ }=\text{ }907200\]