If two non-zero vectors $\vec{P}$ and $\vec{Q}$ are perpendicular to each other then the magnitude of their vector product is $\left(\sin 90^{\circ}=\cos 0^{\circ}=1\right)$,A. $Q^{2} / P$B. $P Q$C. $\sqrt{Q P}$D. $P^{2} / Q$

If two non-zero vectors $\vec{P}$ and $\vec{Q}$ are perpendicular to each other then the magnitude of their vector product is $\left(\sin 90^{\circ}=\cos 0^{\circ}=1\right)$,
A. $Q^{2} / P$
B. $P Q$
C. $\sqrt{Q P}$
D. $P^{2} / Q$

Physics

If two non-zero vectors $\vec{P}$ and $\vec{Q}$ are perpendicular to each other then the magnitude of their vector product is $\left(\sin 90^{\circ}=\cos 0^{\circ}=1\right)$,
A. $Q^{2} / P$
B. $P Q$
C. $\sqrt{Q P}$
D. $P^{2} / Q$

Correct answer is B.

Vector product is calculated as,

$\vec{P}\times\vec{Q}=PQsin90^{\circ}$
$\vec{P}\times\vec{Q}=PQ$

i

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More Material

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