Login/Sign Up
In a single throw of a die, find the probability that the number: \[\left( \mathbf{i} \right)\]will be an even number. \[\left( \mathbf{ii} \right)\] will not be an even number.
In a single throw of a die, find the probability that the number: \[\left( \mathbf{i} \right)\]will be an even number. \[\left( \mathbf{ii} \right)\] will not be an even number.
CBSE | Class 10 | Exercise 13.1 | Selina | Statistics and Probability
In a single throw of a die, find the probability that the number: \[\left( \mathbf{i} \right)\]will be an even number. \[\left( \mathbf{ii} \right)\] will not be an even number.

Solution:

Here, the sample space \[=\text{ }\left\{ 1,\text{ }2,\text{ }3,\text{ }4,\text{ }5,\text{ }6 \right\}\]

\[n\left( s \right)\text{ }=\text{ }6\]

\[\left( i \right)\] If \[E\text{ }=\]event of getting an even number \[=\text{ }\left\{ 2,\text{ }4,\text{ }6 \right\}\]

\[n\left( E \right)\text{ }=\text{ }3\]

Then, probability of a getting an even number \[=~n\left( E \right)/\text{ }n\left( s \right)\text{ }=\text{ }3/6\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]

\[\left( ii \right)\] If \[E\text{ }=\] event of not getting an even number \[=\text{ }\left\{ 1,\text{ }3,\text{ }5 \right\}\]

\[n\left( E \right)\text{ }=\text{ }3\]

Then, probability of a not getting an even number \[=~n\left( E \right)/\text{ }n\left( s \right)\text{ }=\text{ }3/6\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]

i

More Material