(a) The emitter current will be 8 mA
(b) The emitter current will be 10.53 mA
(c) The base current will be 0.53 mA
(d) The base current will be 2 mA
Answer:
The correct options are:
(b) The emitter current will be 10.53 mA
(c) The base current will be 0.53 mA
Explanation:
According to the question,
$ {{I}_{c}}=10mA $
$ {{I}_{c}}=95%\times {{I}_{e}} $
$ {{I}_{c}}=\frac{95}{100}\times {{I}_{e}} $
$ {{I}_{e}}=\frac{10mA\times 100}{95} $
$ {{I}_{e}}=10.53mA $
$ {{I}_{b}}={{I}_{e}}-{{I}_{c}}=10.53-10 $
$ {{I}_{b}}=0.53mA $