Charge held by the oil drop $=1.282 \times 10^{-18} C$
Charge held by one electron $=1.6022 \times 10^{-19} C$
Therefore, No. electrons present in the drop of oil
$\frac{1.282 \times 10^{-18} C}{1.6022 \times 10^{-19} C}$
$=0.8001 \times 10^{1}$
$=8.0$
In Milikan’s experiment, the static electric charge on the oil drops has been obtained by shining $\mathrm{X}$ rays. If the static electric charge on the oil drop is $-1.282 \times 10^{-18} C$, calculate the number of electrons present on it.
In Milikan’s experiment, the static electric charge on the oil drops has been obtained by shining $\mathrm{X}$ rays. If the static electric charge on the oil drop is $-1.282 \times 10^{-18} C$, calculate the number of electrons present on it.