Solution:-
From the figure,
∠P = ∠P (common angle for both triangles)
∠PQR = ∠PRS [from the question]
So, ∆PQR ~ ∆PRS
Then, PQ/PR = PR/PS = QR/SR
Consider PQ/PR = PR/PS
PQ/8 = 8/4
PQ = (8 × 8)/4
PQ = 64/4
PQ = 16 cm
Solution:-
From the figure,
∠P = ∠P (common angle for both triangles)
∠PQR = ∠PRS [from the question]
So, ∆PQR ~ ∆PRS
Then, PQ/PR = PR/PS = QR/SR
Consider PQ/PR = PR/PS
PQ/8 = 8/4
PQ = (8 × 8)/4
PQ = 64/4
PQ = 16 cm