Login/Sign Up
The angle between $A=\hat{i}+\hat{j}$ and $B=\hat{i}-\hat{j}$ is a) $40^{\circ}$ b) $90^{\circ}$ c) $-45^{\circ}$ d) $180^{\circ}$
The angle between $A=\hat{i}+\hat{j}$ and $B=\hat{i}-\hat{j}$ is a) $40^{\circ}$ b) $90^{\circ}$ c) $-45^{\circ}$ d) $180^{\circ}$
CBSE | Class 11 | Motion in a Plane | Physics
The angle between $A=\hat{i}+\hat{j}$ and $B=\hat{i}-\hat{j}$ is a) $40^{\circ}$ b) $90^{\circ}$ c) $-45^{\circ}$ d) $180^{\circ}$

Answer: The correct answer is b) 90o

Given vectors in the question, $\overrightarrow{ A }=\hat{ i }+\hat{ j }$
and $\overrightarrow{ B }=\hat{ i }-\hat{ j }$

∵A→·B→=0\because \overrightarrow{ A } \cdot \overrightarrow{ B }=0

It is clear from the fact that the dot product of the two vectors equals zero that the vectors are perpendicular to one another.
Hence, Angle between vectors, $\vec{A}$ and $\vec{B}$ is $90^{\circ}$

i

More Material