Answer:
Given,
V = 6V
R1 = 2Ω
R2 = 3 Ω
Effective resistance = R
1/R = ½ + 1/3
1/R = 5/6
R = 1.2 Ω
Current flowing through battery, I = V/R = 6/1.2 = 5A
Answer:
Given,
V = 6V
R1 = 2Ω
R2 = 3 Ω
Effective resistance = R
1/R = ½ + 1/3
1/R = 5/6
R = 1.2 Ω
Current flowing through battery, I = V/R = 6/1.2 = 5A