Solution:

Mean of $1, 7, 5, 3, 4$ and $4 = {\frac{(1 + 7 + 5 + 3 + 4 + 4)} {6}} = {\frac{24}{6}} = 4$

Therefore, $m = 4$

It is given that

The mean of $3, 2, 4, 2, 3, 3$ and $p = m -1 = 4 – 1 = 3$

Therefore, $17 + p = 3 \times n \dots$ ,where $n = 7$

$17 + p = 21$

$p = 4$

Arrange the terms in ascending order:

$2, 2, 3, 3, 3, 3, 4, 4$

Mean $= 4^{th}$ term $= 3$

As a result, $q = 3$