Given,

Potential difference $=12 \mathrm{~V}$

1. a) Potential difference = (work done)/(charge moved)

Work done = Potential difference$\times$ charge moved

Therefore, $12 \mathrm{~J}$ of electrical energy is converted into heat and light.

1. b) Work done = potential difference $\times$ charge moved $=12 \times 5=60 \mathrm{~J}$

Therefore, $60 \mathrm{~J}$ of electrical energy is converted into heat and light.

$\text{c})\text{I}=\text{Q}/\text{t}$

$\text{Q}=\text{I}\times \text{t}$

$=2\times 10=20\text{C}$

$\text{ Work done }=\text{ pote }$

$=12\times 20=240~\text{J}$

Therefore, $240 \mathrm{~J}$ of electrical energy is converted into heat and light.