Answer:
Given,
V = 12V
R1, R2, and R3 are linked in a series.
Current through R1 = V/R1 = 12/5 = 2.4 A
Current through R2 = V/R2 = 12/10 = 1.2 A
Current through R3 = V/R3 = 12/30 = 0.4A
Circuit total current = 2.4 + 1.2 + 0.4 = 4A
The circuit’s total resistance is equal to R.
1/R is equal to 1/R1 + 1/R2 + 1/R3
1/R = 1/5 + 1/10 + 1/30
1/R = 10/30
R = 3 ohm