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Two resistors with resistances of 5 and 10 should be connected to a 6V emf battery to get the minimum and maximum current flowing. a) In each situation, how will you connect the resistances? b) In both circumstances, calculate the strength of the total current in the circuit.
Two resistors with resistances of 5 and 10 should be connected to a 6V emf battery to get the minimum and maximum current flowing. a) In each situation, how will you connect the resistances? b) In both circumstances, calculate the strength of the total current in the circuit.
CBSE | Class 10 | Electricity | Lakhmir Singh | Physics
Two resistors with resistances of 5 and 10 should be connected to a 6V emf battery to get the minimum and maximum current flowing. a) In each situation, how will you connect the resistances? b) In both circumstances, calculate the strength of the total current in the circuit.

answer:

a) When the two resistors are linked in series, the current through the resistors is kept to a minimum. The current flow is greatest when the resistors are linked in parallel.
b) If the resistors are connected in series,
5 + 10 = 15 total resistance
1/R is equal to 1/R1 + 1/R2.
1/5 + 1/10 = 1/R
3/10 = 1/R
R = 10/3 R = 10/3 R = 10/3 R = 10/3 R = 10
As a result, the circuit’s total current draw = V/R = 6/(10/3) = 1.8 amps.

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