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When a ray of light is incident normally on one refracting surface of an equilateral prism of refractive index 1.5, the emerging ray $\left[\sin ^{-1}\left(\frac{1}{1.5}\right)=41.8^{\circ}\right]$A) just grazes the second refracting surface.B) is deviated by $20^{\circ}$.C) is deviated by $30^{\circ}$.D) undergoes total internal reflection at second refracting surface.
When a ray of light is incident normally on one refracting surface of an equilateral prism of refractive index 1.5, the emerging ray $\left[\sin ^{-1}\left(\frac{1}{1.5}\right)=41.8^{\circ}\right]$
A) just grazes the second refracting surface.
B) is deviated by $20^{\circ}$.
C) is deviated by $30^{\circ}$.
D) undergoes total internal reflection at second refracting surface.
Physics
When a ray of light is incident normally on one refracting surface of an equilateral prism of refractive index 1.5, the emerging ray $\left[\sin ^{-1}\left(\frac{1}{1.5}\right)=41.8^{\circ}\right]$
A) just grazes the second refracting surface.
B) is deviated by $20^{\circ}$.
C) is deviated by $30^{\circ}$.
D) undergoes total internal reflection at second refracting surface.

Correct answer is D.

Critical angle for the material of prism $C=\sin ^{-1}\left(\frac{1}{\mu}\right)$
$=\sin ^{-1}=42^{\circ}$

since angle of incidence at surface $A B\left(60^{\circ}\right)$ is greater then the critical angle $\left(42^{\circ}\right)$ so total internal reflection takes place.

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