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Solve that equation |z| = z + 1 + 2i.

As per the inquiry,

We have,

   

Subbing z = x + iy, we get,

   

We realize that,

   

   

Looking at genuine and nonexistent parts,

We get,

   

Also, 0 = y + 2

⇒ y = – 2

Subbing the worth of y in

   

We get,

   

   

Consequently, x = 3/2

Consequently, z = x + iy

= 3/2 – 2i