(i) ![\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)(\mathrm{CN})(\mathrm{en})_{2}\right]^{2+}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5830aca5c4a498a25851f5ca5b2a9534_l3.png "Rendered by QuickLaTeX.com")
Ans: Let us assume that the coordination number of Co is X.
Therefore, we can write:
![\[\begin{array}{l} x+0+(-1)+2(0)=+2 \\ x-1=+2 \\ x=+3 \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-1f895f1e5fc75f1121ffe88663b9e04d_l3.png "Rendered by QuickLaTeX.com")
So, the coordination number of cobalt is 
(i)
Ans: Let us assume that the coordination number of Co is X.
Therefore, we can write:
So, the coordination number of cobalt is
