1 + 3 + 7 + 13 + 21 + …
Solution:
Let Tn represent the nth term and let Sn represent the sum to n terms of the given series.
According to the question:
We can rewrite equation (1) as:
Upon subtracting equation (2) from (1) we get
The successive terms differ by 2, 4, 6, 8. As we can see that these differences are in A.P
Now, we have:
Therefore, the sum of the series is n/3 (n2 + 2)