Speed of the kite(V)
![\[=\text{ }10\text{ }m/s\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-b0e0ba61e2797ea876b0ef821a709cc5_l3.png "Rendered by QuickLaTeX.com")
Leave FD alone the tallness of the kite and AB be the stature of the kite and AB be the tallness of the kid.
Presently, let AF
![\[=\text{ }x\text{ }m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-29335ab9f921f2939c9fed4448445646_l3.png "Rendered by QuickLaTeX.com")
Along these lines,
![\[BG\text{ }=\text{ }AF\text{ }=\text{ }x\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-36846cbc79ec22c7ebddd3606e866f79_l3.png "Rendered by QuickLaTeX.com")
What’s more,
![\[dx/dt\text{ }=\text{ }10\text{ }m/s\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-079bbe3ec6b90da77f9b7ba2c00937d0_l3.png "Rendered by QuickLaTeX.com")
From the figure, it’s seen that
![\[GD\text{ }=\text{ }DF\text{ }\text{ }GF\text{ }=\text{ }DF\text{ }\text{ }AB\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-009a1714f7100124a90a924e187a10a9_l3.png "Rendered by QuickLaTeX.com")
![\[=\text{ }\left( 151.5\text{ }\text{ }1.5 \right)\text{ }m\text{ }=\text{ }150\text{ }m\text{ }\left[ As\text{ }AB\text{ }=\text{ }GF \right]\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0a9681b234f8c4e4ce1550998dcd9aa4_l3.png "Rendered by QuickLaTeX.com")
Presently, in ∆ BDG
![\[BG2\text{ }+\text{ }GD2\text{ }=\text{ }BD2\text{ }\left( By\text{ }Pythagoras\text{ }Theorem \right)\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0abb938c315f4336987171cd6d998da1_l3.png "Rendered by QuickLaTeX.com")
![\[x2\text{ }+\text{ }\left( 150 \right)2\text{ }=\text{ }\left( 250 \right)2\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0a2947d4e82d079f873d300796d35127_l3.png "Rendered by QuickLaTeX.com")
![\[x2\text{ }+\text{ }22500\text{ }=\text{ }62500\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-752e4ce0fe8bc0bdf37b8b5445047eea_l3.png "Rendered by QuickLaTeX.com")
![\[x2\text{ }=\text{ }62500\text{ }\text{ }22500\text{ }=\text{ }40000\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-dd12516b5bab193693e85df64e407590_l3.png "Rendered by QuickLaTeX.com")
![\[x\text{ }=\text{ }200\text{ }m\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-0b6a1a9ea4bf80def1215ae062245116_l3.png "Rendered by QuickLaTeX.com")
Leave at first the length of the string alone y m
Along these lines, in ∆ BDG
![\[BG2\text{ }+\text{ }GD2\text{ }=\text{ }BD2\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-c53c568b31df6c21532b9fd13d5157c4_l3.png "Rendered by QuickLaTeX.com")
![\[x2\text{ }+\text{ }\left( 150 \right)2\text{ }=\text{ }y2\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-8dcf3008b1bba45a49d4881c9d2b3cd4_l3.png "Rendered by QuickLaTeX.com")
Separating the two sides w.r.t., t, we have
In this way, the pace of progress of the length of the string is
![\[8\text{ }m/s.\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-bdc9b8cbaf1cdca314d46e2f8c34150a_l3.png "Rendered by QuickLaTeX.com")
