(i)
Energy of the photon 
Where, h denotes Planck’s constant, whose value is 
c denotes the speed of light =
Substituting these values in the expression for E:
Therefore, energy of the photon =
(ii)
The kinetic energy of the emission E_{k}Ek can be calculated as follows:
Therefore, the kinetic energy of the emission = 0.97 eV.
(iii)
The velocity of the photoelectron (v) can be determined using the following expression:
Where 
