(i)
Energy of the photon
Where, h denotes Planck’s constant, whose value is
c denotes the speed of light =
= wavelength of the photon =
Substituting these values in the expression for E:
Therefore, energy of the photon =
(ii)
The kinetic energy of the emission E_{k}Ek can be calculated as follows:
Therefore, the kinetic energy of the emission = 0.97 eV.
(iii)
The velocity of the photoelectron (v) can be determined using the following expression:
Where is the K.El of the emission (in Joules) and ‘m’ denotes the mass of the photoelectron.