An urn contains 5 white and 8 black balls. Two successive drawings of 3 balls at a time are made such that the balls drawn in the first draw are not replaced before the second draw. Find the probability that the first draw gives 3 white balls and the second draw gives 3 black balls.

Let, success in the first draw be getting 3 white balls.
Now, the Probability of success in the first trial is

Let success in the second draw be getting 3 black balls.
Probability of success in the second trial without replacement of the first draw is given by

Hence, the probability that the first draws gives 3 white and the second draw gives 3 black balls, with each trial being independent is given by