The curves are y2 = 9x and y = x
Solving the above equations, we have
![\[\begin{array}{*{35}{l}} {{x}^{2}}~=\text{ }9x\text{ }\Rightarrow \text{ }{{x}^{2}}~\text{ }-9x\text{ }=\text{ }0 \\ x\left( x\text{ }-\text{ }9 \right)\text{ }=\text{ }0 \\ So,\text{ }x\text{ }=\text{ }0,\text{ }9 \\ \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-20f4f067044f6680287a4f66b6dd82d3_l3.png "Rendered by QuickLaTeX.com")
Now, the required area is
Therefore, the required area is 27/2 sq. units.
The curves are y2 = 9x and y = x
Solving the above equations, we have
Now, the required area is
Therefore, the required area is 27/2 sq. units.