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Find the inverse of each of the following matrices:
(i)
(ii)

Solution:

(i) The criteria of existence of inverse matrix is the determinant of a given matrix should not be equal to zero.

\left.\begin{array}{l} \text { Now, }|\mathrm{A}|=\frac{\mathrm{a}+\mathrm{abc}}{\mathrm{a}}-\mathrm{bc}=\frac{\mathrm{a}+\mathrm{abc}-\mathrm{abc}}{\mathrm{a}}=1 \neq 0 \\ \text { Therefore, } \mathrm{A}^{-1} \text { exists. } \\ \text { Cofactors of } \mathrm{A} \text { are } \\ C_{11}=\frac{1+\mathrm{bc}}{\mathrm{a}} \\ C_{12}=-\mathrm{C} \\ C_{21}=-\mathrm{b} \\ C_{22}=\mathrm{a} \\ \text { As, } \operatorname{adj} \mathrm{A}=\left[\begin{array}{ll} \mathrm{C}_{11} & \mathrm{C}_{12} \\ \mathrm{C}_{21} & \mathrm{C}_{22} \end{array}\right]^{\mathrm{T}} \\ \mathrm{A}^{\mathrm{T}} \end{array}\right

(ii) The criteria of existence of inverse matrix is the determinant of a given matrix should not be equal to zero.

Now,

Therefore, exists.

Cofactors of are