![=\mathrm{k}[\mathrm{NO}]^{2}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-077d216724a2565eb77d7647d050fbc2_l3.png "Rendered by QuickLaTeX.com")
![=\mathrm{k}\left[\mathrm{H}_{2} \mathrm{O}_{2}\right]\left[\mathrm{I}^{-}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-6fbf8fa16d66eed94eb61c7ff990758b_l3.png "Rendered by QuickLaTeX.com")
![=\mathrm{k}\left[\mathrm{CH}_{3} \mathrm{CHO}\right]^{\frac{3}{2}}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-9595f161ef5c2ed595df94c7d48dd970_l3.png "Rendered by QuickLaTeX.com")
![=\mathrm{k}\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-69c6cd592c4d4d72f9a6d7046f11ec69_l3.png "Rendered by QuickLaTeX.com")
Solution:
(a) Given rate ![=k[N O]^{2}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-17d88e30a026147c30452f20050d8b7b_l3.png "Rendered by QuickLaTeX.com")
Therefore, order of the reaction 
Dimensions of ![k=\frac{\text { Rete }}{[N O]^{\sharp}}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-d3d74f76dfdd9407df6f407ee6ed33e1_l3.png "Rendered by QuickLaTeX.com")
![\[\begin{array}{l} =\frac{\operatorname{mal} L^{-1} \mathrm{~s}^{-1}}{\left(\mathrm{~mol} L^{-1}\right)^{2}} \\ =\frac{\operatorname{mol} L^{-1} \mathrm{~s}^{-1}}{\operatorname{mol}^{-2} L^{-1}} \\ =L \mathrm{~mol}^{-1} \mathrm{~s}^{-1} \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-2cfae784a65dd7a9db018fb1071c6b58_l3.png "Rendered by QuickLaTeX.com")
(b) Given rate ![=k\left[\mathrm{H}_{2} \mathrm{O}_{2}\right]\left[\mathrm{I}^{-}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-5c971b888139f01590cf3ed062da919d_l3.png "Rendered by QuickLaTeX.com")
Therefore, order of the reaction
Dimensions of ![k=\frac{R a t e}{\left.\left[H_{2} O_{2}\right] I^{-}\right]}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-b902b95a98929e033badfb6369f206e0_l3.png "Rendered by QuickLaTeX.com")
![\[\begin{array}{l} =\frac{m o l}{\left(\operatorname{mol} L^{-1}\right)\left(\operatorname{mol} L^{-1}\right)} \\ =L m o l^{-1} s^{-1} \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-a25e825e1285a9f5915f3a641b81ac7e_l3.png "Rendered by QuickLaTeX.com")
(c) Given rate ![=k\left[\mathrm{CH}_{3} \mathrm{CHO}\right]^{\frac{1}{2}}](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-13a730c5a59556fd9d5ced09284c8bc4_l3.png "Rendered by QuickLaTeX.com")
Therefore, the order of reaction 
Chemical Kinetics
Dimensions of 
(d) Given rate ![=\mathrm{k}=\left[\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}\right]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-4f114c81aa7e47f5203ab263d5f93639_l3.png "Rendered by QuickLaTeX.com")
Therefore, order of the reaction 
Dimension of 
![\[\begin{array}{l} =\frac{\operatorname{mad} L^{-1} s^{-1}}{\operatorname{mal} L^{-1}} \\ =s^{-1} \end{array}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-cf72fada0a7926dca498649064a1f034_l3.png "Rendered by QuickLaTeX.com")
