If one zero of the polynomial is 3 , find the other two zeroes. contexto.140 3 years ago and its factor, dividing by The other two zeroes are 1 and 2 .
![\[\begin{aligned} &=(x-3)\left[\left(x^{2}-(2+1) x+2\right]\right.\\ =&(x-3)\left(x^{2}-2 x-x+2\right) \\ =&(x-3)[x(x-2)-1(x-2)] \\ =&(x-3)(x-1)(x-2) \end{aligned}\]](https://www.learnatnoon.com/s/wp-content/ql-cache/quicklatex.com-9f1817320357c3ef136e20eaaa699a22_l3.png "Rendered by QuickLaTeX.com")
