$I=\int{_{0}^{1}\frac{x}{\sqrt{{{a}^{2}}+{{x}^{2}}}}dx}$ - Noon Academy

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3 years ago

Let

Let

Also when

And when x=a,

Hence ,

Categories: CBSE, Class 12, Definite Integrals, Exercise 16B, Maths, RS Aggarwal

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