$I=\int{_{0}^{1}}\sqrt{\frac{{{\tan }^{-1}}x}{1+{{x}^{2}}}dx}$ - Noon Academy

contexto.140

2 years ago

Let

Let

When ,

Hence,

Categories: CBSE, Class 12, Definite Integrals, Exercise 16B, Maths, RS Aggarwal

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