(i) in the direction of force,

(ii) at an angle of 60^o with the force, and

(iii) normal to the force. (g= 10Nkg^-1)

Solutions:

According to the question –

Force acting on the body is 10 kgf = 10 × 10 N

= 100 N

Displacement is S = 0.5 m

We know that work done can be calculated as –

Work done = force × displacement  

(i) So, work done in direction of force is = W = F × S

W = 100 × 0.5

Therefore, W= 50 J

(ii) Work done when there is an angle of 60 degrees between force and displacement = W

 = F × S cos θ = 100 × 0.5 cos 60⁰

W = 100 × 0.5 × 0.5                            as  [cos 60⁰ = 0.5]

W = 25 J

(iii) When normal to the force, W = F × S cos θ

W = 100 × 0.5 cos 90⁰

W = 100 × 0.5 × 0                               as  [cos 90⁰ = 0]

W = 0