(a) the potential energy at the greatest height,
(b) the kinetic energy on reaching the ground
(c) the total energy at its half waypoint.
Solutions:
(a) Potential energy at maximum height = initial kinetic energy
mgh = 1 / 2 mv2v= 1 / 2 × 0.500 × 15 × 15
Potential energy at maximum height = 56.25J
(b) Kinetic energy on reaching the ground is equal to the potential energy at the greatest height
Therefore, Kinetic energy = 56.25J
(c) Total energy at its halfway point
= 1 / 2 (K + U) = 56.25J