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An electrical appliance having a resistance of 200 ohm is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes (i) in joule, (ii) in kWh
An electrical appliance having a resistance of 200 ohm is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes (i) in joule, (ii) in kWh
Class 10 | Current Energy | ICSE | Selina
An electrical appliance having a resistance of 200 ohm is operated at 200 V. Calculate the energy consumed by the appliance in 5 minutes (i) in joule, (ii) in kWh

We know that,

Resistance = 200 ohm

Voltage = 200 V

time = 5 minutes

As we know,

Energy= V2t / R

(i) Energy in joules

E = [(200)2 × 300] / 200

Hence,

E = 60000 J

(ii) Energy is In kWh

Since1 kWh = 3.6 × 106 J

1 J = 1 / 3.6 × 106 kWh

60000 J = 60000 / 3.6 × 106

Therefore, 60000 J = 0.0167 kWh

i

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