Let the shortest side be $x \mathrm{~m}$. Therefore, according to the question: Hypotenuse $=(2 x-1) m$ Third side $=(x+1) m$ On applying Pythagoras theorem, we get: $\begin{array}{l} (2...
The length of the hypotenuse of a right-angled triangle exceeds the length of the base by $2 \mathrm{~cm}$ and exceeds twice the length of the altitude by $1 \mathrm{~cm}$. Find the length of each side of the triangle.
Let the base and altitude of the right-angled triangle be $x$ and $y \mathrm{~cm}$, respectively Therefore, the hypotenuse will be $(x+2) \mathrm{cm}$. $\therefore(x+2)^{2}=y^{2}+x^{2}$ Again, the...
The hypotenuse of a right-angled triangle is 20 meters. If the difference between the lengths of the other sides be 4 meters, find the other sides
Let one side of the right-angled triangle be $x \mathrm{~m}$ and the other side be $(x+4) \mathrm{m}$. On applying Pythagoras theorem, we have: $\begin{array}{l} 20^{2}=(x+4)^{2}+x^{2} \\...
The area of right -angled triangle is 165 sq meters. Determine its base and altitude if the latter exceeds the former by 7 meters.
Let the base be $x \mathrm{~m}$. Therefore, the altitude will be $(x+7) m$ $\begin{array}{l} \text { Area of a triangle }=\frac{1}{2} \times \text { Base } \times \text { Altitude } \\ \therefore...
The area of right-angled triangle is 96 sq meters. If the base is three time the altitude, find the base.
Let the altitude of the triangle be $x \mathrm{~m}$. Therefore, the base will be $3 x \mathrm{~m}$. $\begin{array}{l} \text { Area of a triangle }=\frac{1}{2} \times \text { Base } \times \text {...
The area of a right triangle is $600 \mathrm{~cm}^{2}$. If the base of the triangle exceeds the altitude by $10 \mathrm{~cm}$, find the dimensions of the triangle.
Let the altitude of the triangle be $x \mathrm{~cm}$ Therefore, the base of the triangle will be $(x+10) \mathrm{cm}$ $\begin{array}{l} \text { Area of triangle }=\frac{1}{2} x(x+10)=600 \\...
A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced. Find the dimensions of the garden.
Let the length and breadth of the rectangular garden be $x$ and $y$ meter, respectively. Given: $x y=180 \mathrm{sq} \mathrm{m}$$\ldots(i)$ and $\begin{array}{l} 2 y+x=39 \\ \Rightarrow x=39-2 y...
The length of a rectangle is thrice as long as the side of a square. The side of the square is $4 \mathrm{~cm}$, more than the width of the rectangle. Their areas being equal, find the dimensions.
Let the breadth of rectangle be $x \mathrm{~cm}$. According to the question: Side of the square $=(x+4) \mathrm{cm}$ Length of the rectangle $=\{3(x+4)\} \mathrm{cm}$ It is given that the areas of...
The sum of the areas of two squares is $640 \mathrm{~m}^{2}$. If the difference in their perimeter be $64 \mathrm{~m}$, find the sides of the two square
Let the length of the side of the first and the second square be $x$ and $y \cdot$ respectively. According to the question: $x^{2}+y^{2}=640$ Also, $\begin{array}{l} 4 x-4 y=64 \\ \Rightarrow x-y=16...
A rectangular filed in $16 \mathrm{~m}$ long and $10 \mathrm{~m}$ wide. There is a path of uniform width all around it, having an area of $120 \mathrm{~m}^{2}$. Find the width of the path
Let the width of the path be $x \mathrm{~m}$. $\therefore$ Length of the field including the path $=16+x+x=16+2 x$ Breadth of the field including the path $=10+x+x=10+2 x$ Now, (Area of the field...
The perimeter of a rectangular plot is $62 \mathrm{~m}$ and its area is 288 sq meters. Find the dimension of the plot
Let the length and breadth of the rectangular plot be $x$ and $y$ meter, respectively. Therefore, we have: $\begin{array}{l} \text { Perimeter }=2(x+y)=62 \quad \ldots . .(i) \text { and } \\ \text...
The length of a hall is 3 meter more than its breadth. If the area of the hall is 238 sq meters, calculate its length and breadth.
Let the breath of the rectangular hall be $x$ meter. Therefore, the length of the rectangular hall will be $(x+3)$ meter. According to the question: $\begin{array}{l} x(x+3)=238 \\ \Rightarrow...
The length of a rectangular field is three times its breadth. If the area of the field be 147 sq meters, find the length of the field.
Let the length and breadth of the rectangle be $3 x \mathrm{~m}$ and $x \mathrm{~m}$, respectively. According to the question: $\begin{array}{l} 3 x \times x=147 \\ \Rightarrow 3 x^{2}=147 \\...
The length of rectangle is twice its breadth and its areas is $288 \mathrm{~cm} 288 \mathrm{~cm}^{2}$. Find the dimension of the rectangle.
Let the length and breadth of the rectangle be $2 x \mathrm{~m}$ and $x \mathrm{~m}$, respectively. According to the question: $\begin{array}{l} 2 x \times x=288 \\ \Rightarrow 2 x^{2}=288 \\...
Two water taps together can fill a tank in 6 hours. The tap of larger diameter takes 9 hours less than the smaller one to fill the tank separately. Find the time which each tap can separately fill the tank.
Let the tap of smaller diameter fill the tank in $x$ hours. $\therefore$ Time taken by the tap of larger diameter to fill the tank $=(x-9) h$ Suppose the volume of the tank be $V$. Volume of the...
Two pipes running together can fill a tank in $11 \frac{1}{9}$ minutes. If on pipe takes 5 minutes more than the other to fill the tank separately, find the time in which each pipe would fill the tank separately.
Let the time taken by one pipe to fill the tank be $x$ minutes. $\therefore$ Time taken by the other pipe to fill the tank $=(x+5) \min$ Suppose the volume of the tank be $V$. Volume of the tank...
Two pipes running together can fill a cistern in $3 \frac{1}{13}$ minutes. If one pipe takes 3 minutes more than the other to fill it, find the time in which each pipe would fill the cistern.
Let one pipe fills the cistern in $x$ mins. Therefore, the other pipe will fill the cistern in $(x+3)$ mins. Time taken by both, running together, to fill the cistern $=3 \frac{1}{13} \min...
A takes 10 days less than the time taken by $B$ to finish a piece of work. If both $A$ and $B$ together can finish the work in 12 days, find the time taken by B to finish the work.
Let B takes $x$ days to complete the work. Therefore, A will take $(x-10)$ days. $\begin{array}{l} \therefore \frac{1}{x}+\frac{1}{(x-10)}=\frac{1}{12} \\ \Rightarrow...
A motorboat whose speed is $9 \mathrm{~km} / \mathrm{hr}$ in still water, goes $15 \mathrm{~km}$ downstream and comes back in a total time of 3 hours 45 minutes. Find the speed of the stream.
Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. $\therefore$ Downstream speed $=(9+x) \mathrm{km} / \mathrm{hr}$ Upstream speed $=(9-x) \mathrm{km} / \mathrm{hr}$ Distance covered...
The speed of a boat in still water is $8 \mathrm{~km} / \mathrm{hr}$. It can go $15 \mathrm{~km}$ upstream and $22 \mathrm{~km}$ downstream is 5 hours. Fid the speed of the stream.
Speed of the boat in still water $=8 \mathrm{~km} / \mathrm{hr}$. Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. $\therefore$ Speed upstream $=(8-x) \mathrm{km} / \mathrm{hr}$ Speed...
A motor boat whose speed in still water is $178 \mathrm{~km} / \mathrm{hr}$, takes 1 hour more to go $24 \mathrm{~km}$ upstream than to return to the same spot. Find the speed of the stream.
Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. Given: Speed of the boat $=18 \mathrm{~km} / \mathrm{hr}$ $\therefore$ Speed downstream $=(18+x) \mathrm{km} / h r$ Speed upstream...
The distance between Mumbai and Pune is $192 \mathrm{~km}$. Travelling by the Deccan Queen, it takes 48 minutes less than another train. Calculate the speed of the Deccan Queen if the speeds of the two train differ by $20 \mathrm{~km} / \mathrm{hr}$
Let the speed of the Deccan Queen be $x \mathrm{~km} / \mathrm{hr}$. According to the question: Speed of another train $=(x-20) \mathrm{km} / \mathrm{hr}$ $\begin{array}{l} \therefore...
A passenger train takes 2 hours less for a journey of $300 \mathrm{~km}$ if its speed is increased by $5 \mathrm{~km} / \mathrm{hr}$ from its usual speed. Find its usual speed.
Let the usual speed $x \mathrm{~km} / \mathrm{hr}$. According to the question: $\begin{array}{l} \frac{300}{x}-\frac{300}{(x+5)}=2 \\ \Rightarrow \frac{300(x+5)-300 x}{x(x+5)}=2 \\ \Rightarrow...
A train covers a distance of $90 \mathrm{~km}$ at a uniform speed. Had the speed been $15 \mathrm{~km} / \mathrm{hr}$ more, it would have taken 30 minutes less for the journey. Find the original speed of the train.
Let the original speed of the train be $x \mathrm{~km} / \mathrm{hr}$. According to the question: $\frac{90}{x}-\frac{90}{(x+15)}=\frac{1}{2}$ $\begin{array}{l} \Rightarrow \frac{90(x+15)-90...
A train travels $180 \mathrm{~km}$ at a uniform speed. If the speed had been $9 \mathrm{~km} / \mathrm{hr}$ more, it would have taken 1 hour less for the same journey. Find the speed of the train.
Let the speed of the train be xkmph The time taken by the train to travel $180 \mathrm{~km}$ is $\frac{180}{\mathrm{x}} \mathrm{h}$ The increased speed is $\mathrm{x}+9$ The time taken is...
A train travels at a certain average speed for a distanced of $54 \mathrm{~km}$ and then travels a distance of 63 $\mathrm{km}$ at an average speed of $6 \mathrm{~km} / \mathrm{hr}$ more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed?
Let the first speed of the train be $x \mathrm{~km} / \mathrm{h}$. Time taken to cover $54 \mathrm{~km}=\frac{54}{x} h .$ New speed of the train $=(x+6) \mathrm{km} / \mathrm{h}$ $\therefore$ Time...
A train covers a distance of $480 \mathrm{~km}$ at a uniform speed. If the speed had been $8 \mathrm{~km} / \mathrm{hr}$ less then it would have taken 3 hours more to cover the same distance. Find the usual speed of the train.
Let the usual speed of the train be $x \mathrm{~km} / \mathrm{h}$. $\therefore$ Reduced speed of the train $=(x-8) \mathrm{km} / \mathrm{h}$ Total distance to be covered $=480 \mathrm{~km}$ Time...
The hypotenuse of a right-angled triangle is 1 meter less than twice the shortest side. If the third side 1 meter more than the shortest side, find the side, find the sides of the triangle.
Let the shortest side be $x \mathrm{~m}$. Therefore, according to the question: Hypotenuse $=(2 x-1) m$ Third side $=(x+1) m$ On applying Pythagoras theorem, we get: $\begin{array}{l} (2...
The length of the hypotenuse of a right-angled triangle exceeds the length of the base by $2 \mathrm{~cm}$ and exceeds twice the length of the altitude by $1 \mathrm{~cm}$. Find the length of each side of the triangle.
Let the base and altitude of the right-angled triangle be $x$ and $y \mathrm{~cm}$, respectively Therefore, the hypotenuse will be $(x+2) \mathrm{cm}$. $\therefore(x+2)^{2}=y^{2}+x^{2}$ Again, the...
The hypotenuse of a right-angled triangle is 20 meters. If the difference between the lengths of the ther sides be 4 meters, find the other sides.
Let one side of the right-angled triangle be $x \mathrm{~m}$ and the other side be $(x+4) m$. On applying Pythagoras theorem, we have: $\begin{array}{l} 20^{2}=(x+4)^{2}+x^{2} \\ \Rightarrow...
The area of right -angled triangle is 165 sq meters. Determine its base and altitude if the latter exceeds the former by 7 meters.
Let the base be $x \mathrm{~m}$. Therefore, the altitude will be $(x+7) m$. Area of a triangle $=\frac{1}{2} \times$ Base $\times$ Altitude $\begin{array}{l} \therefore \frac{1}{2} \times x...
The area of right-angled triangle is 96 sq meters. If the base is three time the altitude, find the base.
Let the altitude of the triangle be $x \mathrm{~m}$. Therefore, the base will be $3 x \mathrm{~m}$. $\begin{array}{l} \text { Area of a triangle }=\frac{1}{2} \times \text { Base } \times \text {...
The area of a right triangle is $600 \mathrm{~cm}^{2}$. If the base of the triangle exceeds the altitude by $10 \mathrm{~cm}$, find the dimensions of the triangle.
Let the altitude of the triangle be $x \mathrm{~cm}$ Therefore, the base of the triangle will be $(x+10) \mathrm{cm}$ $\begin{array}{l} \text { Area of triangle }=\frac{1}{2} x(x+10)=600 \\...
A farmer prepares rectangular vegetable garden of area 180 sq meters. With 39 meters of barbed wire, he can fence the three sides of the garden, leaving one of the longer sides unfenced. Find the dimensions of the garden.
Let the length and breadth of the rectangular garden be $x$ and $y$ meter, respectively. Given: $x y=180 s q m.....(i)and$ $\begin{array}{l} 2 y+x=39 \\ \Rightarrow x=39-2 y \end{array}$ Putting the...
The length of a rectangle is thrice as long as the side of a square. The side of the square is $4 \mathrm{~cm}$ more than the width of the rectangle. Their areas being equal, find the dimensions.
Let the breadth of rectangle be $x \mathrm{~cm}$. According to the question: Side of the square $=(x+4) \mathrm{cm}$ Length of the rectangle $=\{3(x+4)\} \mathrm{cm}$ It is given that the areas of...
The sum of the areas of two squares is $640 \mathrm{~m}^{2}$. If the difference in their perimeter be $64 \mathrm{~m}$, find the sides of the two square.
Let the length of the side of the first and the second square be $x$ and $y \cdot$ respectively. According to the question: $x^{2}+y^{2}=640$ Also, $\begin{array}{l} 4 x-4 y=64 \\ \Rightarrow x-y=16...
A rectangular filed in $16 \mathrm{~m}$ long and $10 \mathrm{~m}$ wide. There is a path of uniform width all around it, having an area of $120 \mathrm{~m}^{2}$. Find the width of the path
Let the width of the path be $x \mathrm{~m}$. $\therefore$ Length of the field including the path $=16+x+x=16+2 x$ Breadth of the field including the path $=10+x+x=10+2 x$ Now, (Area of the field...
The perimeter of a rectangular plot is $62 \mathrm{~m}$ and its area is 288 sq meters. Find the dimension of the plot
Let the length and breadth of the rectangular plot be $x$ and $y$ meter, respectively. Therefore, we have: $\begin{array}{l} \text { Perimeter }=2(x+y)=62 \quad \ldots . .(i) \text { and } \\ \text...
The length of a hall is 3 meter more than its breadth. If the area of the hall is 238 sq meters, calculate its length and breadth.
Let the breath of the rectangular hall be $x$ meter. Therefore, the length of the rectangular hall will be $(x+3)$ meter. According to the question: $\begin{array}{l} x(x+3)=238 \\ \Rightarrow...
The length of a rectangular field is three times its breadth. If the area of the field be 147 sq meters, find the length of the field.
Let the length and breadth of the rectangle be $3 x \mathrm{~m}$ and $x \mathrm{~m}$, respectively. According to the question: $\begin{array}{l} 3 x \times x=147 \\ \Rightarrow 3 x^{2}=147 \\...
The length of rectangle is twice its breadth and its areas is $288 \mathrm{~cm}^{2}$. Find the dimension of the rectangle.
Let the length and breadth of the rectangle be $2 x \mathrm{~m}$ and $x \mathrm{~m}$, respectively. According to the question: $2 x \times x=288$ $\Rightarrow 2 x^{2}=288$ $\Rightarrow x^{2}=144$...
Two water taps together can fill a tank in 6 hours. The tap of larger diameter takes 9 hours less than the smaller one to fill the tank separately. Find the time which each tap can separately fill the tank.
Let the tap of smaller diameter fill the tank in $x$ hours. $\therefore$ Time taken by the tap of larger diameter to fill the tank $=(x-9) h$ Suppose the volume of the tank be $V$. Volume of the...
Two pipes running together can fill a tank in $11 \frac{1}{9}$ minutes. If on pipe takes 5 minutes more than the other to fill the tank separately, find the time in which each pipe would fill the tank separately.
Let the time taken by one pipe to fill the tank be $x$ minutes. $\therefore$ Time taken by the other pipe to fill the tank $=(x+5) \min$ Suppose the volume of the tank be $V$. Volume of the tank...
Two pipes running together can fill a cistern in $3 \frac{1}{13}$ minutes. If one pipe takes 3 minutes more than the other to fill it, find the time in which each pipe would fill the cistern.
Let one pipe fills the cistern in $x$ mins. Therefore, the other pipe will fill the cistern in $(x+3)$ mins. Time taken by both, running together, to fill the cistern $=3 \frac{1}{13} \min...
A takes 10 days less than the time taken by $\mathrm{B}$ to finish a piece of work. If both $\mathrm{A}$ and $\mathrm{B}$ together can finish the work in 12 days, find the time taken by $\mathrm{B}$ to finish the work.
Let B takes $x$ days to complete the work. Therefore, A will take $(x-10)$ days. $\begin{array}{l} \therefore \frac{1}{x}+\frac{1}{(x-10)}=\frac{1}{12} \\ \Rightarrow...
A motorboat whose speed is $9 \mathrm{~km} / \mathrm{hr}$ in still water, goes $15 \mathrm{~km}$ downstream and comes back in a total time of 3 hours 45 minutes. Find the speed of the stream.
Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. $\therefore$ Downstream speed $=(9+x) \mathrm{km} / \mathrm{hr}$ Upstream speed $=(9-x) \mathrm{km} / \mathrm{hr}$ Distance covered...
The speed of a boat in still water is $8 \mathrm{~km} / \mathrm{hr}$. It can go $15 \mathrm{~km}$ upstream and $22 \mathrm{~km}$ downstream is 5 hours. Fid the speed of the stream
Speed of the boat in still water $=8 \mathrm{~km} / \mathrm{hr}$. Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. $\therefore$ Speed upstream $=(8-x) \mathrm{km} / \mathrm{hr}$ Speed...
A motor boat whose speed in still water is $178 \mathrm{~km} / \mathrm{hr}$, takes 1 hour more to go $24 \mathrm{~km}$ upstream than to return to the same spot. Find the speed of the stream
Let the speed of the stream be $x \mathrm{~km} / \mathrm{hr}$. Given: Speed of the boat $=18 \mathrm{~km} / \mathrm{hr}$ $\therefore$ Speed downstream $=(18+x) \mathrm{km} / \mathrm{hr}$ Speed...
The distance between Mumbai and Pune is $192 \mathrm{~km}$. Travelling by the Deccan Queen, it takes 48 minutes less than another train. Calculate the speed of the Deccan Queen if the speeds of the two train differ by $20 \mathrm{~km} / \mathrm{hr}$.
Let the speed of the Deccan Queen be $x \mathrm{~km} / \mathrm{hr}$. According to the question: Speed of another train $=(x-20) \mathrm{km} / \mathrm{hr}$ $\begin{array}{l} \therefore...
A passenger train takes 2 hours less for a journey of $300 \mathrm{~km}$ if its speed is increased by $5 \mathrm{~km} / \mathrm{hr}$ from its usual speed. Find its usual speed.
Let the usual speed $x \mathrm{~km} / \mathrm{hr}$. According to the question: $\begin{array}{l} \frac{300}{x}-\frac{300}{(x+5)}=2 \\ \Rightarrow \frac{300(x+5)-300 x}{x(x+5)}=2 \\ \Rightarrow...
A train covers a distance of $90 \mathrm{~km}$ at a uniform speed. Had the speed been $15 \mathrm{~km} / \mathrm{hr}$ more, it would have taken 30 minutes less for the journey. Find the original speed of the train.
Let the original speed of the train be $x \mathrm{~km} / \mathrm{hr}$. According to the question: $\frac{90}{x}-\frac{90}{(x+15)}=\frac{1}{2}$ $\begin{array}{l} \Rightarrow \frac{90(x+15)-90...
A train travels $180 \mathrm{~km}$ at a uniform speed. If the speed had been $9 \mathrm{~km} / \mathrm{hr}$ more, it would have taken 1 hour less for the same journey. Find the speed of the train.
Let the speed of the train be xkmph The time taken by the train to travel $180 \mathrm{~km}$ is $\frac{180}{\mathrm{x}} \mathrm{h}$ The increased speed is $\mathrm{x}+9$ The time taken is...
A train travels at a certain average speed for a distanced of $54 \mathrm{~km}$ and then travels a distance of 63 $\mathrm{km}$ at an average speed of $6 \mathrm{~km} / \mathrm{hr}$ more than the first speed. If it takes 3 hours to complete the total journey, what is its first speed?
Let the first speed of the train be $x \mathrm{~km} / \mathrm{h}$. Time taken to cover $54 \mathrm{~km}=\frac{54}{x} h \quad\left(\right.$ Time $\left.=\frac{\text { Distance }}{\text { Speed...
A train covers a distance of $480 \mathrm{~km}$ at a uniform speed. If the speed had been $8 \mathrm{~km} / \mathrm{hr}$ less then it would have taken 3 hours more to cover the same distance. Find the usual speed of the train.
Let the usual speed of the train be $x \mathrm{~km} / \mathrm{h}$. $\therefore$ Reduced speed of the train $=(x-8) \mathrm{km} / \mathrm{h}$ Total distance to be covered $=480 \mathrm{~km}$ Time...
While boarding an aeroplane, a passengers got hurt. The pilot showing promptness and concern, made arrangements to hospitalize the injured and so the plane started late by 30 minutes. To reach the destination, $1500 \mathrm{~km}$ away, in time, the pilot increased the speed by $100 \mathrm{~km} /$ hour. Find the original speed of the plane. Do you appreciate the values shown by the pilot, namely promptness in providing help to the injured and his efforts to reach in time?
Let the original speed of the plane be $x \mathrm{~km} / \mathrm{h}$. $\therefore$ Actual speed of the plane $=(x+100) \mathrm{km} / \mathrm{h}$ Distance of the journey $=1500 \mathrm{~km}$ Time...
A truck covers a distance of $150 \mathrm{~km}$ at a certain average speed and then covers another 200 $\mathrm{km}$ at an average speed which is $20 \mathrm{~km}$ per hour more than the first speed. If the truck covers the total distance in 5 hours, find the first speed of the truck.
Let the first speed of the truck be $x \mathrm{~km} / \mathrm{h}$. $\therefore$ Time taken to cover $150 \mathrm{~km}=\frac{150}{x} h \quad\left(\right.$ Time $\left.=\frac{\text { Dis tan ce...
Two years ago, man’s age was three times the square of his son’s age. In three years’ time, his age will be four time his son’s age. Find their present ages.
Let son's age 2 years ago be $x$ years. Then, Man's age 2 years ago $=3 x^{2}$ years $\therefore$ Sons present age $=(x+2)$ years Man's present age $=\left(3 x^{2}+2\right)$ years In three years...
The product of Tanvy’s age (in years) 5 years ago and her age is 8 years later is 30 . Find her present age.
Let the present age of Meena be $x$ years. According to the question: $\begin{array}{l} (x-5)(x+8)=30 \\ \Rightarrow x^{2}+3 x-40=30 \\ \Rightarrow x^{2}+3 x-70=0 \\ \Rightarrow x^{2}+(10-7) x-70=0...
The sum of the ages of a boy and his brother is 25 years, and the product of their ages in years is 126 . Find their ages.
Let the present ages of the boy and his brother be $x$ years and $(25-x)$ years. According to the question: $\begin{array}{l} x(25-x)=126 \\ \Rightarrow 25 x-x^{2}=126 \\ \Rightarrow x^{2}-(18-7)...
The sum of reciprocals of Meena’s ages (in years ) 3 years ago and 5 years hence $\frac{1}{3}$. Find her present ages.
Let the present age of Meena be $x$ years Meena's age 3 years ago $=(x-3)$ years Meena's age 5 years hence $=(x+5)$ years According to the given condition, $\frac{1}{x-3}+\frac{1}{x+5}=\frac{1}{3}$...
One year ago, man was 8 times as old as his son. Now, his age is equal to the square of his son’s age. Find their present ages.
Let the present age of the son be $x$ years. $\therefore$ Present age of the $\operatorname{man}=x^{2}$ years One year ago, Age of the son $=(x-1)$ years Age of the man $=\left(x^{2}-1\right)$ years...
A dealer sells an article for 75 and gains as much per cent as the cost priced of the article. Find the cost price of the article.
Let the cost price of the article be $x$ $\therefore$ Gain percent $=x \%$ According to the given condition, $\Rightarrow \frac{100 x+x^{2}}{100}=75$ $\Rightarrow x^{2}+100 x=7500$ $\Rightarrow...
A man buys a number of pens for Rs. 180 . If he had bought 3 more pens for the same amount, each pen would have cost him Rs. 3 less. How many pens did he buy?
Let the total number of pens be $x$. According to the question: $\begin{array}{l} \frac{80}{x}-\frac{80}{x+4}=1 \\ \Rightarrow \frac{80(x+4)-80 x}{x(x+4)}=1 \\ \Rightarrow \frac{80+320-80 x}{x^{2}+4...
In a class test, the sum of the marks obtained by $\mathrm{P}$ in mathematics and science is 28 . Had he got 3 more marks in mathematics and 4 marks less in science, the product of marks obtained in the two subjects would have been $180 .$ Find the marks obtained by him in the two subjects separately.
Let the marks obtained by $P$ in mathematics and science be $x$ and $(28-x)$, respectively. According to the given condition, $\begin{array}{l} (x+3)(28-x-4)=180 \\ \Rightarrow(x+3)(24-x)=180 \\...
A person on tour has Rs. 10800 for his expenses. If he extends his tour by 4 days, he has to cut down his daily expenses by Rs. 90 . Find the original duration of the tour.
Let the original duration of the tour be $x$ days. $\therefore \text { Original daily expenses }=\text { γ } \frac{10,800}{x}$ If he extends his tour by 4 days, then his new daily expenses...
If the price of a book is reduced by Rs. 5, a person can buy 4 more books for 300 . Find the original price of the book.
Let the original price of the book be $Rs x$. $\therefore$ Number of books bought at original price for $Rs. 600=\frac{600}{x}$ $\therefore$ Number of books bought at reduced price for...
Some students planned a picnic. The total budget for food was Rs. $2000 .$ But, 5 students failed to attend the picnic and thus the cost for food for each member increased by Rs. $20 .$ How many students attended the picnic and how much did each student pay for the food?
Let $x$ be the number of students who planned a picnic. $\therefore$ Original cost of food for each member $=$ γ $\frac{2000}{x}$ Five students failed to attend the picnic. So, $(x-5)$ students...
In a class test, the sum of Kamal’s marks in mathematics and English is 40 . Had he got 3 marks more in mathematics and 4 marks less in English, the product of the marks would have been 360 . Find his marks in two subjects separately.
Let the marks of Kamal in mathematics and English be $x$ and $y$, respectively. According to the question: $x+y=40$ Also, $\begin{array}{l} (x+3)(y-4)=360 \\ \Rightarrow(x+3)(40-x-4)=360 \quad[\text...
300 apples are distributed equally among a certain number of students. Had there been 10 more students, each would have received one apple less. Find the number of students.
Let the total number of students be $x$. According to the question: $\begin{array}{l} \frac{300}{x}-\frac{300}{x+10}=1 \\ \Rightarrow \frac{300(x+10)-300 x}{x(x+10)}=1 \\ \Rightarrow \frac{300...
A teacher on attempting to arrange the students for mass drill in the form of solid square found that 24 students were left. When he increased the size of the square by one student, he found that he was short of 25 students. Find the number of students.
Let there be $x$ rows. Then, the number of students in each row will also be $x$. $\therefore$ Total number of students $=\left(x^{2}+24\right)$ According to the question: $\begin{array}{l}...
The sum of a number and its reciprocal is $2 \frac{1}{30}$. Find the number.
Let the required number be $x$. According to the given condition, $\begin{array}{l} x+\frac{1}{x}=2 \frac{1}{30} \\ \Rightarrow \frac{x^{2}+1}{x}=\frac{61}{30} \\ \Rightarrow 30 x^{2}+30=61 x \\...
The numerator of a fraction is 3 less than its denominator. If 1 is added to the denominator, the fraction is decreased by $\frac{1}{15}$. Find the fraction.
Let the denominator of the required fraction be $x$. Numerator of the required fraction $=x-3$ $\therefore$ Original fraction $=\frac{x-3}{x}$ If 1 is added to the denominator, then the new fraction...
The denominator of a fraction is 3 more than its numerator. The sum of the fraction and its reciprocal is $2 \frac{9}{10}$. Find the fraction.
Let the numerator be $x$. $\therefore$ Denominator $=x+3$ $\therefore$ Original number $=\frac{x}{x+3}$ According to the question: $\frac{x}{x+3}+\frac{1}{\left(\frac{x}{x+3}\right)}=2 \frac{9}{10}$...
A two-digit number is such that the product of its digits is 14 . If 45 is added to the number, the digit interchange their places. Find the number.
Let the digits at units and tens places be $x$ and $y$, respectively. $\therefore x y=14$ $\Rightarrow y=\frac{14}{x}$ According to the question: $\begin{array}{l} (10 y+x)+45=10 x+y \\ \Rightarrow...
A two-digit number is 4 times the sum of its digits and twice the product of digits. Find the number.
Let the digits at units and tens places be $x$ and $y$, respectively. Original number $=10 y+x$ According to the question: $\begin{array}{l} 10 y+x=4(x+y) \\ \Rightarrow 10 y+x=4 x+4 y \\...
Three consecutive positive integers are such that the sum of the square of the first and product of the other two is 46 . Find the integers.
Let the three consecutive positive integers be $x, x+1$ and $x+2$. According to the given condition, $\begin{array}{l} x^{2}+(x+1)(x+2)=46 \\ \Rightarrow x^{2}+x^{2}+3 x+2=46 \\ \Rightarrow 2...
The difference of the squares of two natural numbers is 45 . The square of the smaller number is four times the larger number. Find the numbers.
Let the greater number be $x$ and the smaller number be $y$. According to the question: $\begin{array}{l} x^{2}-y^{2}=45 \\ y^{2}=4 x \end{array}$ From (i) and (ii), we get: $x^{2}-4 x=45$...
Divide two natural numbers, the sum of whose squares is 25 times their sum and also equal to 50 times their difference.
Let the two natural numbers be $x$ and $y$. According to the question: $\begin{array}{l} x^{2}+y^{2}=25(x+y) \quad \ldots \ldots(i) \\ x^{2}+y^{2}=50(x-y) \end{array}$ From (i) and (ii), we get:...
Divide 16 into two parts such that twice the square of the larger part exceeds the square of the smaller part by 164 .
Let the larger and smaller parts be $x$ and $y$, respectively. According to the question: $\begin{array}{l} x+y=16 .....(i) \\ 2 x^{2}=y^{2}+164.....(ii) \end{array} \quad$ From (i), we get:...
Divide 27 into two parts such that the sum of their reciprocal is $\frac{3}{20}$.
Let the two parts be $x$ and $(27-x)$. According to the given condition, $\begin{array}{l} \frac{1}{x}+\frac{1}{27-x}=\frac{3}{20} \\ \Rightarrow \frac{27-x+x}{x(27-x)}=\frac{3}{20} \\ \Rightarrow...
Divide 57 into two parts whose product is 680 .
Let the two parts be $x$ and $(57-x)$. According to the given condition, $\begin{array}{l} x(57-x)=680 \\ \Rightarrow 57 x-x^{2}=680 \\ \Rightarrow x^{2}-57 x+680=0 \\ \Rightarrow x^{2}-40 x-17...
The sum of natural number and its reciprocal is $\frac{65}{8}$. Find the number.
Let the natural number be $x$. According to the given condition, $\begin{array}{l} x+\frac{1}{x}=\frac{65}{8} \\ \Rightarrow \frac{x^{2}+1}{x}=\frac{65}{8} \\ \Rightarrow 8 x^{2}+8=65 x \\...
The sum of the squares two consecutive multiples of 7 is 1225 . Find the multiples.
Let the required consecutive multiplies of 7 be $7 x$ and $7(x+1)$. According to the given condition, $(7 x)^{2}+[7(x+1)]^{2}=1225$ $\Rightarrow 49 x^{2}+49\left(x^{2}+2 x+1\right)=1225$...
The difference of two natural numbers is 5 and the difference of heir reciprocals is $\frac{5}{14}$. Find the numbers.
Let the required natural numbers be $x$ and $(x+5)$. Now, $x<x+5$ $\therefore \frac{1}{x}>\frac{1}{x+5}$ According to the given condition, $\begin{array}{l}...
The difference of two natural number is 3 and the difference of their reciprocals is $\frac{3}{28}$. Find the numbers.
Let the required natural numbers be $x$ and $(x+3)$. Now, $x<x+3$ $\therefore \frac{1}{x}>\frac{1}{x+3}$ According to the given condition, $\begin{array}{l}...
The sum of two natural numbers is 15 and the sum of their reciprocals is $\frac{3}{10}$. Find the numbers.
Let the required natural numbers be $x$ and $(15-x)$. According to the given condition, $\begin{array}{l} \frac{1}{x}+\frac{1}{15-x}=\frac{3}{10} \\ \Rightarrow \frac{15-x+x}{x(15-x)}=\frac{3}{10}...
The sum of two natural numbers is 9 and the sum of their reciprocals is $\frac{1}{2}$. Find the numbers.
Let the required natural numbers be $x$ and $(9,-x)$. According to the given condition, $\begin{array}{l} \frac{1}{x}+\frac{1}{9-x}=\frac{1}{2} \\ \Rightarrow \frac{9-x+x}{x(9-x)}=\frac{1}{2} \\...
Find the two consecutive positive even integers whose product is 288.
Let the two consecutive positive even integers be $x$ and $(x+2)$. According to the given condition, $\begin{array}{l} x(x+2)=288 \\ \Rightarrow x^{2}+2 x-288=0 \\ \Rightarrow x^{2}+18 x-16 x-288=0...
Find the tow consecutive positive odd integer whose product s 483 .
Let the two consecutive positive odd integers be $x$ and $(x+2)$. According to the given condition, $\begin{array}{l} x(x+2)=483 \\ \Rightarrow x^{2}+2 x-483=0 \\ \Rightarrow x^{2}+23 x-21 x-483=0...
Find two consecutive multiples of 3 whose product is 648.
Let the required consecutive multiples of 3 be $3 x$ and $3(x+1)$. According to the given condition, $\begin{array}{l} 3 x \times 3(x+1)=648 \\ \Rightarrow 9\left(x^{2}+x\right)=648 \\ \Rightarrow...
Two natural number differ by 3 and their product is 504 . Find the numbers.
Let the required numbers be $x$ and $(x+3)$. According to the question: $\begin{array}{l} x(x+3)=504 \\ \Rightarrow x^{2}+3 x=504 \\ \Rightarrow x^{2}+3 x-504=0 \\ \Rightarrow x^{2}+(24-21) x-504=0...
The product of two consecutive positive integers is 306 . Find the integers.
Let the two consecutive positive integers be $x$ and $(x+1)$. According to the given condition, $\begin{array}{l} x(x+1)=306 \\ \Rightarrow x^{2}+x-306=0 \\ \Rightarrow x^{2}+18 x-17 x-306=0 \\...
The sum of the squares of two consecutive positive even numbers is 452 . Find the numbers.
Let the two consecutive positive even numbers be $x$ and $(x+2)$. According to the given condition, $\begin{array}{l} x^{2}+(x+2)^{2}=452 \\ \Rightarrow x^{2}+x^{2}+4 x+4=452 \\ \Rightarrow 2...
The sum of the squares to two consecutive positive odd numbers is 514 . Find the numbers.
Let the two consecutive positive odd numbers be $x$ and $(x+2)$. According to the given condition, $\begin{array}{l} x^{2}+(x+2)^{2}=514 \\ \Rightarrow x^{2}+x^{2}+4 x+4=514 \\ \Rightarrow 2 x^{2}+4...
The sum of the squares of two consecutive positive integers is 365 . Find the integers.
Let the required two consecutive positive integers be $x$ and $(x+1)$. According to the given condition, $\begin{array}{l} x^{2}+(x+1)^{2}=365 \\ \Rightarrow x^{2}+x^{2}+2 x+1=365 \\ \Rightarrow 2...
The sum of two natural number is 28 and their product is 192 . Find the numbers.
Let the required number be $x$ and $(28-x)$. According to the given condition, $\begin{array}{l} x(28-x)=192 \\ \Rightarrow 28 x-x^{2}=192 \\ \Rightarrow x^{2}-28 x+192=0 \\ \Rightarrow x^{2}-16...
The sum of natural number and its positive square root is $132 .$ Find the number.
Let the required natural number be $x$. According to the given condition, $x+\sqrt{x}=132$ Putting $\sqrt{x}=y$ or $x=y^{2}$, we get $y^{2}+y=132$ $\Rightarrow y^{2}+y-132=0$ $\Rightarrow y^{2}+12...
The sum of a natural number and its square is $156 .$ Find the number.
Let the required natural number be $x$. According to the given condition, $x+x^{2}=156$ $\Rightarrow x^{2}+x-156=0$ $\Rightarrow x^{2}+13 x-12 x-156=0$ $\Rightarrow x(x+13)-12(x+13)=0$...