Answer:

$ v=1MHz={{10}^{6}}Hz $

$ v=\frac{1}{2\pi \sqrt{LC}} $

$ Or,\sqrt{LC}=\frac{1}{2\pi v} $

$ LC=\frac{1}{{{(2\pi v)}^{2}}}=\frac{1}{4\times 3.14\times 3.14\times {{10}^{12}}} $

$ LC=\frac{{{10}^{-12}}}{39.44} $

$ LC=2.54\times {{10}^{-14}}{{\sec }^{2}} $