Solutions:
We know that, 1 joule = 1N × 1m
Also, 1 N = 105 dyne and 1 m = 102 cm
Therefore, we have –
1 joule = 105 dyne × 102 cm
= 107 dyne × cm = 107 erg
Hence, 1 joule = 107 erg
Solutions:
We know that, 1 joule = 1N × 1m
Also, 1 N = 105 dyne and 1 m = 102 cm
Therefore, we have –
1 joule = 105 dyne × 102 cm
= 107 dyne × cm = 107 erg
Hence, 1 joule = 107 erg