Find the mean of the following distribution.
Find the mean of the following distribution.
Class interval 0-10 10-20 20-30 30-40 40-50
Frequency 10 6 8 12 5

Solution:

Class mark, xi = (upper class limit + lower class limit)/2

Class interval Frequency fi Class mark xi fixi
0-10 10 5 50
10-20 6 15 90
20-30 8 25 200
30-40 12 35 420
40-50 5 45 225
Total Ʃfi = 41 Ʃfixi = 985

Mean = Ʃfixi/ Ʃfi

= 985/41

= 24.024

= 24.02 (approx)

Hence the mean of the distribution is 24.02.