Marks obtained by 40 students in a short assessment are given below, where a and b are two missing data.
Marks obtained by 40 students in a short assessment are given below, where a and b are two missing data.
Marks 5 6 7 8 9
No. of students 6 a 16 13 b

If the mean of the distribution is 7.2, find a and b.

Solution:

Marks (x) No. of students (f) fx
5 6 30
6 a 6a
7 16 112
8 13 104
9 b 9b
Total Ʃf = 35+a+b Ʃfx = 246+6a+9b

Given number of students = 40

Ʃf = 35+a+b = 40

a+b = 40-35 = 5

a = 5-b ……(i)

Mean = Ʃfx/Ʃf

Given mean = 7.2

( 246+6a+9b) /40 = 7.2

( 246+6a+9b) = 40×7.2

( 246+6a+9b) = 288

6a+9b = 288-246

6a+9b = 288-246

6a+9b = 42

2a+3b = 14 …..(ii)

Substitute (i) in (ii)

2(5-b)+3b = 14

10-2b+3b = 14

10+b = 14

b = 14-10 = 4

a = 5-4 = 1

Hence the value of a and b is 1 and 4 respectively.