Given
The number of electrons that pass across a conductor,
The number of electrons in n =\(6.25\times {{10}^{16}}\) is the number of electrons in n = \(6.25\times {{10}^{16}}\)
The time it takes to get from point A to point B is 2 seconds, and the temperature is \(1.6\times {{10}^{-19}}\)degrees Celsius.
Assume I’m the current that’s coursing through the conductor.
Currently, I = ne / t
As a result, I = \(6.25\times {{10}^{16}}\times\)\(1.6\times {{10}^{-19}}\)/ 2
I = 5 × 10-3 A
I = 5 m A
As a result, a current of 5 mA travels from B to A.